A bomb of mass 16 kg at rest explodes into two pieces of masses 4

Subject

Physics

Class

NEET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

If the position of a moving particle, with respect to time be, x(t) = 1 + t − t2, then, the acceleration of particle is given by (assume all measurements in MKS)

  • − 1 ms-2

  • − 1.5 ms-2

  • − 2 ms-2

  • − 2.5 ms-2


2.

A ball is dropped from a tower of height h. The duration (t0) of motion, when it reaches bottom of the tower is given by

  • 2hg

  • hg

  • 2 hg

  • 4hg


3.

For the given position-time (x − t) graph , the interval in  which velocity is zero, is

  

  • (t3 − t1)

  • (t3 − t2)

  • (t5 − t4)

  • (t5 − t2)


4.

A particle moves along the x-axis as x = u (t −2s) + a (t − 2s)2. The initial velocity of the particle is

  • u − 2a

  • u − 4a

  • 2a − u

  • 2a − 3u


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5.

The centre of mass of three particles of mass m= 1.0 kg, m2 = 2.0 kg, and m3 = 3.0 kg at the corners of an equilateral triangle 1.0 m on a side, as shown in figure

  

  • 712m, 34m

  • 512m, 35m

  • 513m, 35m

  • 812m, 35m


6.

A system consists of two point masses M and m (< M). The centre of mass of the system is

  • at the middle of m and M

  • nearer to M

  • nearer to m

  • at the position of large mass


7.

A ball is projected horizontally with a velocity of 5 m/s from the top of a building 19.6 m high, flow long will the ball take to hit the ground?

  • 2 s

  • 2 s

  • 3 s

  • 3 s


8.

A body of mass 3 kg is acted on by a force which varies as shown in the graph. The momentum acquired is given by

    

  • zero

  • 5 N-s

  • 30 N-s

  • 50 N-s


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9.

Two perfectly elastic particles A and B of equal masses travelling along the line joining, them with velocity 15 m/s and 20 m/s respectively collide. Their velocities after the elastic collision will be (in m/s) respectively.

  • 0 and 25

  • 5 and 20

  • 10 and 15

  • 20 and 15


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10.

A bomb of mass 16 kg at rest explodes into two pieces of masses 4 kg and 12 kg. The  velocity of the 12 kg mass is 4 ms-1 . The kinetic energy of the other mass is

  • 192 J

  • 96 J

  • 144 J

  • 288 J


D.

288 J

By law of conservation of linear momentum, the velocity of the 4 kg mass is 12 ms-1. Therefore,

KE = 1 × 4 × 1222 = 288 J


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