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SSCCGL Quantitative Aptitude Solved Question Paper 2011

Multiple Choice Questions

81.

The area of the square inscribed in a circle of radius 8 cm is

256 sq. cm.
250 sq. cm.
128 sq. cm.
128 sq. cm.

188 Views

82.

X and Y are centres of circles of radii 9cm and 2 cm respectively, XY = 17cm. Z is the centre of a circle of radius r cm which touches the above circles externally. Given that $angle XZY space equals space 90 degree comma$ the value of r is

13 cm
6 cm
9 cm
9 cm

182 Views

83.

I is the incentre of a triangle ABC. If $angle ABC space equals space 65 degree$ and $angle ACB space equals space 55 degree comma$ then the value of $angle BIC$ is

130°
120°
140°
140°

204 Views

84.

If the radii of two circles be 6 cm and 3 cm and the length of the transverse common tangent be 8 cm, then the distance between the two centres is

$square root of 145 space cm$
$square root of 140 space cm$
$square root of 150 space cm$
$square root of 150 space cm$

665 Views

85.

The ratio between the number of sides of two regular polygons is 1 : 2 and the ratio between their interior angles is 2 : 3. The number of sides of these polygons is respectively.

6, 12
5, 10
4, 8
4, 8

371 Views

86.

Two posts are x metres apart and the height of one is double that of the other. If from the mid-point of the line joining their feet, an observer finds the angular elevations of their tops to be complementary, then the height (in metres) of the shorter post is

$fraction numerator straight x over denominator 2 square root of 2 end fraction$
$straight x over 4$
$straight x square root of 2$
$straight x square root of 2$

145 Views

87.
If θ is a positive acute angle and tan 2θ tan 3θ = 1, then the value of
$left parenthesis 2 space cos squared straight theta fraction numerator 5 straight theta over denominator 2 end fraction minus 1 right parenthesis$ is

$negative 1 half$

1

0

0

tan 2θ. tan 3θ = 1
$rightwards double arrow space space space tan space 3 straight theta space equals space fraction numerator 1 over denominator tan space 2 straight theta end fraction space equals space cot space 2 straight theta rightwards double arrow space space space tan space 3 straight theta space equals space tan space left parenthesis 90 degree minus 2 straight theta right parenthesis rightwards double arrow space space space 3 straight theta space equals space 90 degree space minus space 2 straight theta space space space rightwards double arrow space space space 5 straight theta space equals space 90 degree rightwards double arrow space space space space straight theta space equals space 18 degree$

$therefore space space space space 2 space cos squared fraction numerator 5 straight theta over denominator 2 end fraction minus 1 space equals space 2 cos squared 45 degree space minus space 1 equals space 2 space cross times space 1 half space minus space 1 space equals space 0$

188 Views

88.

If $sin space 17 degree space equals space straight x over straight y comma$ then the value of $left parenthesis sec space 17 degree space minus space sin space 73 degree right parenthesis$ is

$fraction numerator straight y squared over denominator straight x square root of straight y squared minus straight x squared end root end fraction$
$fraction numerator straight x squared over denominator straight y square root of straight y squared minus straight x squared end root end fraction$
$fraction numerator straight x squared over denominator straight y square root of straight x squared minus straight y squared end root end fraction$
$fraction numerator straight x squared over denominator straight y square root of straight x squared minus straight y squared end root end fraction$