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SSCCGL Quantitative Aptitude Solved Question Paper 2011

Multiple Choice Questions

101.

If $9 square root of straight x space equals space square root of 12 space plus space square root of 147 comma$ then x = ?

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102.
$cube root of 1 minus 127 over 343 end root$ is equal to

$5 over 9$

$1 minus 1 over 7$

$4 over 7$

$1 minus 2 over 7$

$1 minus 1 over 7$

$cube root of 1 minus 127 over 343 end root space equals space cube root of fraction numerator 343 minus 127 over denominator 343 end fraction end root space equals space cube root of 216 over 343 end root space equals space 6 over 7 equals space space 1 minus 1 over 7$

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103.

If the sum of two numbers be multiplied by each number separately, the products so obtained are 247 and 114. The sum of the numbers is

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104.

Find a number, one-seventh of which exceeds its eleventh part by 100.

1925
1825
1540
1340

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105.

$square root of 6 plus square root of 6 plus square root of 6 plus... end root end root end root space equals space ?$

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106.

The square root of $open parentheses fraction numerator square root of 3 space plus space square root of 2 over denominator square root of 3 space minus space square root of 2 end fraction close parentheses$ is

$square root of 3 space plus space square root of 2$
$square root of 3 space minus space square root of 2$
$square root of 2 space plus-or-minus space square root of 3$
$square root of 2 minus square root of 3$

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107.

The remainder when 3²¹ is divided by 5 is

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108.

The value of $fraction numerator 2 begin display style 1 third end style minus 1 begin display style 2 over 11 end style over denominator 3 plus begin display style fraction numerator 1 over denominator 3 plus begin display style fraction numerator 1 over denominator 3 plus begin display style 1 third end style end fraction end style end fraction end style end fraction$ is

$38 over 109$
$109 over 38$
1
$116 over 109$

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109.

The last digit of (1001)²⁰⁰⁸ + 1002 is

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110.

The value of
$fraction numerator 3 square root of 2 over denominator square root of 3 space plus space square root of 6 end fraction space minus space fraction numerator 4 square root of 3 over denominator square root of 6 space end root begin display style plus end style begin display style square root of 2 end style end fraction space plus space fraction numerator square root of 6 over denominator square root of 3 begin display style space end style begin display style plus end style begin display style space end style begin display style square root of 2 end style end fraction$ is