If the sum of two numbers be multiplied by each number separately, the products so obtained are 247 and 114. The sum of the numbers is
19
20
21
23
Find a number, one-seventh of which exceeds its eleventh part by 100.
1925
1825
1540
1340
The last digit of (1001)2008 + 1002 is
0
3
4
6
B.
3
(1001)2008 + 1002
Unit digit in 18 + 1002
= 1 + 1002 = 1003
Hence, last digit is 3.