If the sum of two numbers be multiplied by each number separately, the products so obtained are 247 and 114. The sum of the numbers is
19
20
21
23
A.
19
Let two numbers be x and y respectively.
According to the question,
(x) x (x + y) = 247
x2 + xy = 247 ...(i)
And, (y) x (x + y) = 114
y2 + xy = 114 ...(ii)
Adding (i) and (ii), we get
x2 + y2 + 2xy = 361
⟹ (x + y)2 = 361
⟹ (x + y) = 19
∴ Sum of the numbers are 19.
Find a number, one-seventh of which exceeds its eleventh part by 100.
1925
1825
1540
1340