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SSCCGL Quantitative Aptitude Solved Question Paper 2011

Multiple Choice Questions

101.

If $9 square root of straight x space equals space square root of 12 space plus space square root of 147 comma$ then x = ?

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102.

$cube root of 1 minus 127 over 343 end root$ is equal to

$5 over 9$
$1 minus 1 over 7$
$4 over 7$
$1 minus 2 over 7$

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103.

If the sum of two numbers be multiplied by each number separately, the products so obtained are 247 and 114. The sum of the numbers is

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104.
Find a number, one-seventh of which exceeds its eleventh part by 100.

1925

1825

1540

1340

1925

Let the number be x.
According to the question,
$straight x space cross times space 1 over 7 space minus space straight x over 11 space equals space 100 rightwards double arrow space space fraction numerator 11 straight x minus 7 straight x over denominator 77 end fraction space equals space 100 rightwards double arrow space space space 4 straight x space equals space 77 space cross times space 100 rightwards double arrow space space space space straight x space equals space fraction numerator 77 space cross times space 100 over denominator 4 end fraction rightwards double arrow space space space straight x space equals space 1925$

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105.

$square root of 6 plus square root of 6 plus square root of 6 plus... end root end root end root space equals space ?$

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106.

The square root of $open parentheses fraction numerator square root of 3 space plus space square root of 2 over denominator square root of 3 space minus space square root of 2 end fraction close parentheses$ is

$square root of 3 space plus space square root of 2$
$square root of 3 space minus space square root of 2$
$square root of 2 space plus-or-minus space square root of 3$
$square root of 2 minus square root of 3$

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107.

The remainder when 3²¹ is divided by 5 is

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108.

The value of $fraction numerator 2 begin display style 1 third end style minus 1 begin display style 2 over 11 end style over denominator 3 plus begin display style fraction numerator 1 over denominator 3 plus begin display style fraction numerator 1 over denominator 3 plus begin display style 1 third end style end fraction end style end fraction end style end fraction$ is

$38 over 109$
$109 over 38$
1
$116 over 109$

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109.

The last digit of (1001)²⁰⁰⁸ + 1002 is

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110.

The value of
$fraction numerator 3 square root of 2 over denominator square root of 3 space plus space square root of 6 end fraction space minus space fraction numerator 4 square root of 3 over denominator square root of 6 space end root begin display style plus end style begin display style square root of 2 end style end fraction space plus space fraction numerator square root of 6 over denominator square root of 3 begin display style space end style begin display style plus end style begin display style space end style begin display style square root of 2 end style end fraction$ is