If the sum of two numbers be multiplied by each number separately, the products so obtained are 247 and 114. The sum of the numbers is
19
20
21
23
Find a number, one-seventh of which exceeds its eleventh part by 100.
1925
1825
1540
1340
The remainder when 321 is divided by 5 is
1
2
3
4
C.
3
The unit digit of 321 is 3.
The remainder, when a number is divided by 5, always the unit digit itself. i .e. 3 is the right answer.