Test Series

Take Zigya Full and Sectional Test Series. Time it out for real assessment and get your results instantly.

Test Yourself

Practice and master your preparation for a specific topic or chapter. Check you scores at the end of the test.

SSCCGL Quantitative Aptitude Solved Question Paper 2012

Multiple Choice Questions

In a division sum, the divisor is 4 times the quotient and twice the remainder. If a and b are respectively the divisor and the dividend, then

$fraction numerator 4 straight b minus straight a squared over denominator straight a end fraction equals 3$
$fraction numerator 4 straight b minus 2 straight a over denominator straight a squared end fraction space equals space 2$
$left parenthesis straight a plus 1 right parenthesis squared space equals space 4 straight b$
$left parenthesis straight a plus 1 right parenthesis squared space equals space 4 straight b$

552 Views

If 738A6A is divisible by 11, then the value of A is

279 Views

The product of two number is 1575 and their quotient is 9/7. Then the sum of the numbers is

297 Views

The value of $fraction numerator left parenthesis 8.3 right parenthesis to the power of 3.6 end exponent cross times space left parenthesis 9 right parenthesis to the power of 2.7 end exponent over denominator left parenthesis 81 right parenthesis to the power of 4.2 end exponent space cross times space left parenthesis 3 right parenthesis end fraction$ is

126 Views

square root of 6 plus square root of 6 plus 6 plus.... end root end root

is equal to

116 Views

6.
The sum of the squares of two natural consecutive odd numbers is 394. The sum of the numbers is

24

32

40

40

Let x and x+2 be the two consecutive odd numbers.
$rightwards double arrow space space space straight x squared plus space left parenthesis straight x plus 2 right parenthesis squared space equals space 394 rightwards double arrow space space straight x squared plus straight x squared plus 4 plus 4 straight x space equals space 394 rightwards double arrow space space 2 straight x squared plus 4 straight x minus 390 space equals space 0 rightwards double arrow space straight x squared plus 2 straight x minus 195 space equals space 0$

$rightwards double arrow space straight x squared plus 15 straight x minus 13 straight x minus 195 space equals space 0 rightwards double arrow space space straight x left parenthesis straight x plus 15 right parenthesis space minus 13 left parenthesis straight x plus 15 right parenthesis space equals space 0 rightwards double arrow space left parenthesis straight x minus 13 right parenthesis thin space left parenthesis straight x plus 15 right parenthesis space equals space 0 rightwards double arrow space space straight x space equals space 13 space comma space minus 15 rightwards double arrow space straight x space equals space 13$
So, the numbers are (x = 13), (x+2 = 13+2 = 15)
∴ The required sum = 13 + 15 = 28

Shortcut Method:
By mental operation,
13² + 15² = 169 + 225 = 394
∴ The required sum = 13 + 15 = 28

174 Views

When (67⁶⁷ + 67) is divided by 68, the remainder is

364 Views

A can do a piece of work in 24 days, B in 52 days and C in 64 days. All begin to do it together, but A leaves after 6 days and B leaves 6 days before the completion of the work. How many days did the work last?

720/29
20
18
18

240 Views

The square root of:
$fraction numerator left parenthesis 0.75 right parenthesis cubed over denominator 1 minus 0.75 end fraction space plus space left square bracket 0.75 space plus space left parenthesis 0.75 right parenthesis squared plus 1 right square bracket$ is

143 Views

10.

Given that $square root of 4096 space equals space 64 comma$ the value of $square root of 4096 space plus space square root of 40.96 end root space plus space square root of 0.004096 end root$ is