Given that  the value of  is from Quantitative Aptitude SSC

Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

In a division sum, the divisor is 4 times the quotient and twice the remainder. If a and b are respectively the divisor and the dividend, then

  • fraction numerator 4 straight b minus straight a squared over denominator straight a end fraction equals 3
  • fraction numerator 4 straight b minus 2 straight a over denominator straight a squared end fraction space equals space 2
  • left parenthesis straight a plus 1 right parenthesis squared space equals space 4 straight b
  • left parenthesis straight a plus 1 right parenthesis squared space equals space 4 straight b
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2.

If 738A6A is divisible by 11, then the value of A is

  • 6

  • 3

  • 9

  • 9

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3.

The product of two number is 1575 and their quotient is 9/7. Then the sum of the numbers is

  • 74

  • 78

  • 80

  • 80

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4.

The value of fraction numerator left parenthesis 8.3 right parenthesis to the power of 3.6 end exponent cross times space left parenthesis 9 right parenthesis to the power of 2.7 end exponent over denominator left parenthesis 81 right parenthesis to the power of 4.2 end exponent space cross times space left parenthesis 3 right parenthesis end fraction is

  • 3

  • 6

  • 9

  • 9

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5. square root of 6 plus square root of 6 plus 6 plus.... end root end root is equal to
  • 2

  • 5

  • 4

  • 4

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6.

The sum of the squares of two natural consecutive odd numbers is 394. The sum of the numbers is

  • 24

  • 32

  • 40

  • 40

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7.

When (6767 + 67) is divided by 68, the remainder is

  • 1

  • 63

  • 66

  • 66

364 Views

8.

A can do a piece of work in 24 days, B in 52 days and C in 64 days. All begin to do it together, but A leaves after 6 days and B leaves 6 days before the completion of the work. How many days did the work last?

  • 720/29

  • 20

  • 18

  • 18

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9.

The square root of:
fraction numerator left parenthesis 0.75 right parenthesis cubed over denominator 1 minus 0.75 end fraction space plus space left square bracket 0.75 space plus space left parenthesis 0.75 right parenthesis squared plus 1 right square bracket is 

  • 1

  • 2

  • 3

  • 3

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10.

Given that square root of 4096 space equals space 64 comma the value of square root of 4096 space plus space square root of 40.96 end root space plus space square root of 0.004096 end root is

  • 70.4

  • 70.464

  • 71.104

  • 71.104


B.

70.464

square root of 4096 space equals space 64
therefore space space square root of 40.96 end root space equals space square root of 4096 over 100 end root space equals space 64 over 10 space equals space 6.4
square root of 0.004096 end root space equals space square root of 4096 over 1000000 end root space equals space 64 over 1000 space equals space 0.064
∴  Expression = 64 + 6.4 + 0.064 = 70.464
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