One of the angles of a right-angled is 15°, and the hypotenuse

Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

The principal which gives ₹ 1 interest per day at a rate of 5% simple interest per annum is

  • ₹ 5000

  • ₹ 7300 

  • ₹ 36500

  • ₹ 36500

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2.

When Principal = ₹ S, rate of interest  = 2r % p.a., then a person will get after 3 years at compound interest

  • ₹ space fraction numerator 6 Sr over denominator 100 end fraction
  • ₹ space straight S open parentheses 1 plus straight r over 100 close parentheses cubed
  • ₹ space straight S open parentheses 1 plus straight r over 50 close parentheses cubed
  • ₹ space straight S open parentheses 1 plus straight r over 50 close parentheses cubed
282 Views

3.

The sum of money which becomes ₹ 2420 at 10% rate of compound interest after two years is

  • ₹ 2000

  • ₹ 1000

  • ₹ 2500

  • ₹ 2500

368 Views

4.

From a solid right circular cylinder of length 4 cm and diameter 6 cm, a conical cavity of the same height and base is hollowed out. The whole surface area of the remaining solid (in square cm) is

  • 48 π

  • 15 π

  • 63 π

  • 53 π

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5.

A spherical ball of radius 1 cm is dropped into a conical vessel of radius 3 cm and slant height 6 cm. The volume of water (in cm3), that can just immerse the ball, is

  • fraction numerator 5 straight pi over denominator 3 end fraction
  • straight pi over 3
  • 3 straight pi
  • 3 straight pi
1295 Views

6.

The in-radius of a triangle is 6 cm, and the sum of the lengths of its sides is 50 cm. The area of the triangle (in square cm.)

  • 150

  • 50

  • 300

  • 300

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7.

One of the angles of a right-angled is 15°, and the hypotenuse is 1 metre. The area of the triangle (in square cm) is

  • 1220

  • 1200

  • 1250

  • 1250


C.

1250



Area of triangle  =  1 half cross times straight B cross times straight P
Base space of space triangle space space equals space cos space 15 space degree space equals space straight B over straight H
cos space 15 degree space equals space cos thin space left parenthesis 45 degree space minus space 30 degree right parenthesis
       equals space cos space 45 degree. space cos space 30 degree space plus space sin space 45 degree. space sin space 30 degree
equals space fraction numerator 1 over denominator square root of 2 end fraction cross times space fraction numerator square root of 3 over denominator 2 end fraction space plus space fraction numerator 1 over denominator square root of 2 end fraction space cross times space 1 half space equals space fraction numerator square root of 3 plus 1 over denominator 2 square root of 2 end fraction
 
Perpendicular of triangle  = sin space 15 degree space equals space straight P over straight H
   sin space 15 degree space equals space sin space left parenthesis 45 degree space minus space 30 degree right parenthesis
space equals space sin space 45 degree space cross times space cos space 30 degree space minus space cos space 45 degree space cross times space sin space 30 degree
equals space fraction numerator 1 over denominator square root of 2 end fraction cross times fraction numerator square root of 3 over denominator 2 end fraction space minus space fraction numerator 1 over denominator square root of 2 end fraction cross times space 1 half space equals space fraction numerator square root of 3 minus 1 over denominator 2 square root of 2 end fraction
Now, Area of triangle  equals space 1 half cross times open parentheses fraction numerator square root of 3 begin display style minus end style begin display style 1 end style over denominator 2 square root of 2 end fraction cross times fraction numerator square root of 3 begin display style minus end style begin display style 1 end style over denominator 2 square root of 2 end fraction close parentheses
                        equals space 1 half space cross times space fraction numerator left parenthesis 3 minus 1 right parenthesis over denominator 8 end fraction space equals space 1 over 8 space cm squared
equals space 1 over 8 space cross times space 10000 space equals space 1250 space cm squared



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8.

Assume that a drop of water is spherical and its diameter is one-tenth of a cm. A conical glass has a height equal to the diameter of its rim. If 32000 drops of water fill the glass completely, then the height of the glass (in cm) is

  • 3

  • 1

  • 4

  • 4

315 Views

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9.

If the height of a cylinder is 4 times its circumference, the volume of the cylinder in terms of its circumference c, is

  • fraction numerator 2 straight c cubed over denominator straight pi end fraction
  • 4 πc cubed
  • straight c cubed over straight pi
  • straight c cubed over straight pi
455 Views

10.

If the ratio of the angles of a quadrilateral is 2 : 7 : 2 : 7, then it is a

  • trapezium

  • parallelogram

  • square

  • square

514 Views

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