Each member of a club contributes as much rupees and as much pai

Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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1.

Each member of a club contributes as much rupees and as much paise as the number of members of the club. If the total contribution is Rs. 2525, then the number of members of the club is

  • 60

  • 45

  • 55

  • 50


D.

50

Let Number of members in the club  = x
According to the question,



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2.

The numerator of a fraction is multiple of two numbers. One of the numbers is greater than the other by 2. The greater number is smaller than the denominator by 4. If the denominator 7+C (C > -7) is a constant, then the minimum value of the fraction is

  • 5

  • 1 fifth
  • -5

  • -5

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3.

A number when divided by the sum of 555 and 445 gives two times their difference as quotient and 30 as the remainder. The number is

  • 220030

  • 22030

  • 1220

  • 1220

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4.

When a number x is divided by a divisor it is seen that the divisor = 4 times the quotient = double the remainder. If the remainder is 80 then the value of x is

  • 6480

  • 9680

  • 8460

  • 8460

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5.

On dividing a certain number by 342 we get 47 as remainder. If the same number is divided by 18, what will be the remainder?

  • 15

  • 11

  • 17

  • 17

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6.

The sum of three numbers is 252. If the first number is thrice and the second and third number is two-third of the first, then the second number is

  • 41

  • 21

  • 42

  • 42

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7.

The sum of three numbers is 252. If the first number is thrice the second and third number is two-third of the first, then the second number is

  • 255

  • 260

  • 265

  • 265

302 Views

8.

The sum of three numbers is 2, the 1st number is 1/2 times the 2nd number and the 3rd number is 1/4 times the 2nd number. The 2nd number is

  • 7/6

  • 8/7

  • 9/8

  • 9/8

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9.

Three numbers are in Arithmetic Progression (AP) whose sum is 30 and the product is 910. Then the greatest number in the AP is

  • 17

  • 15

  • 13

  • 13

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10.

Simplify;
cube root of negative 2197 end root space cross times space cube root of negative 125 end root space plus space cube root of 27 over 512 end root

  • 492 over 7
  • 520 over 3
  • 554 over 7
  • 554 over 7
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