Simplify; from Quantitative Aptitude SSC - CGL Year 2016 Free S

Subject

Quantitative Aptitude

Class

SSCCGL Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

1.

Each member of a club contributes as much rupees and as much paise as the number of members of the club. If the total contribution is Rs. 2525, then the number of members of the club is

  • 60

  • 45

  • 55

  • 50

2701 Views

2.

The numerator of a fraction is multiple of two numbers. One of the numbers is greater than the other by 2. The greater number is smaller than the denominator by 4. If the denominator 7+C (C > -7) is a constant, then the minimum value of the fraction is

  • 5

  • 1 fifth
  • -5

  • -5

1245 Views

3.

A number when divided by the sum of 555 and 445 gives two times their difference as quotient and 30 as the remainder. The number is

  • 220030

  • 22030

  • 1220

  • 1220

424 Views

4.

When a number x is divided by a divisor it is seen that the divisor = 4 times the quotient = double the remainder. If the remainder is 80 then the value of x is

  • 6480

  • 9680

  • 8460

  • 8460

454 Views

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5.

On dividing a certain number by 342 we get 47 as remainder. If the same number is divided by 18, what will be the remainder?

  • 15

  • 11

  • 17

  • 17

385 Views

6.

The sum of three numbers is 252. If the first number is thrice and the second and third number is two-third of the first, then the second number is

  • 41

  • 21

  • 42

  • 42

314 Views

7.

The sum of three numbers is 252. If the first number is thrice the second and third number is two-third of the first, then the second number is

  • 255

  • 260

  • 265

  • 265

302 Views

8.

The sum of three numbers is 2, the 1st number is 1/2 times the 2nd number and the 3rd number is 1/4 times the 2nd number. The 2nd number is

  • 7/6

  • 8/7

  • 9/8

  • 9/8

240 Views

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9.

Three numbers are in Arithmetic Progression (AP) whose sum is 30 and the product is 910. Then the greatest number in the AP is

  • 17

  • 15

  • 13

  • 13

706 Views

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10.

Simplify;
cube root of negative 2197 end root space cross times space cube root of negative 125 end root space plus space cube root of 27 over 512 end root

  • 492 over 7
  • 520 over 3
  • 554 over 7
  • 554 over 7


B.

520 over 3
equals space cube root of negative 2197 end root space cross times space space cube root of negative 125 end root space divided by space cube root of 27 over 512 end root
equals cube root of negative 13 space cross times space minus 13 space cross times space minus 13 end root space cross times space cube root of negative 5 space cross times space minus 5 space cross times space minus 5 end root space divided by space cube root of fraction numerator 3 space cross times space 3 space cross times space 3 over denominator 8 space cross times space 8 space cross times space 8 end fraction end root
equals negative 13 space cross times space minus 5 space divided by 3 over 8
equals space fraction numerator 65 space cross times space 8 over denominator 3 end fraction space equals space 520 over 3

324 Views

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