A gas cylinder contains 12 x 10²⁴ molecules of oxygen gas.
if Avogadro's number is 6 x 10²³; Calculate:

i) The mass of oxygen present in the cylinder
ii) The volume of oxygen at S.T.P present in the cylinder. [O=16]

straight i right parenthesis space 1 space mole space oxygen space molecule space equals space 6.022 space straight x space 10 to the power of 23 space moleules space 19.93 space moles space of space oxygen space molecule space equals space 12 space straight x 10 to the power of 24 space molecules Number space of space moles space of space Oxygen space space equals space fraction numerator Mass space of space straight O subscript 2 over denominator Molar space mass space of space straight O subscript 2 end fraction ii right parenthesis space Mass space of space straight O subscript 2 space equals space 32 space straight x space 19.93 space equals space 637.76 space straight g 6.022 space straight x space 10 to the power of 23 space molecules space occupies space 22.4 space straight L 12 space straight x space 10 to the power of 24 space molecules space occupies space space equals space fraction numerator 12 space straight x space 10 to the power of 24 space straight x space 22.4 over denominator 6.022 space straight x space 10 to the power of 23 end fraction space equals space 446.36 space straight L space volume.

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A gas cylinder contains 12 x 1024 molecules of oxygen gas.if Avogadro's number is 6 x 1023; Calculate: i) The mass of oxygen present in the cylinderii) The volume of oxygen at S.T.P present in the cylinder. [O=16]

Mole Concept And Stoichiometry

Frank Modern Certificate Chemistry Part II

A gas cylinder contains 12 x 10²⁴ molecules of oxygen gas.
if Avogadro's number is 6 x 10²³; Calculate:

i) The mass of oxygen present in the cylinder
ii) The volume of oxygen at S.T.P present in the cylinder. [O=16]