The central atoms in CH₄, NH3 and H₂O are all said to have similar hybridisation but the bond angle H – A – H (where A is C, N or O) is different in each case. Explain stating in which case it is maximum and in which case it is minimum.

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Anonymous · Accepted Answer

Due to sp³ hybridization, four such identical orbitals are symmetrically dispersed in space at an angle of 109°-28', which is the bond angle in methane. In NH₃, there is one lone pair occupying one of the four symmetrical orbitals and due to its expansive nature suppresses the other three orbitals closer together at an angle of 107° and in H₂O, there are two lone pairs as oxygen which suppresses the O – H bonds further closer together and they have an angle of 104.5°. Hence, H – A – H is maximum in CH₄ and minimum in H₂O.

The central atoms in CH₄, NH3 and H₂O are all said to have similar hybridisation but the bond angle H – A – H (where A is C, N or O) is different in each case. Explain stating in which case it is maximum and in which case it is minimum.

Chemical Bonding and Molecular Structure

Chemistry Part I

The central atoms in CH4, NH3 and H2O are all said to have similar hybridisation but the bond angle H – A – H (where A is C, N or O) is different in each case. Explain stating in which case it is maximum and in which case it is minimum.

Chemical Bonding and Molecular Structure

Chemistry Part I

The central atoms in CH₄, NH3 and H₂O are all said to have similar hybridisation but the bond angle H – A – H (where A is C, N or O) is different in each case. Explain stating in which case it is maximum and in which case it is minimum.