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How many moles of AgBr (K_sp = 5 × 10^–13 mol² L^–2) will dissolve in a 0·01 M NaBr solution (NaBr is completely dissociated into Na⁺ and Br^-ion).

The complete ionisation of NaBr is represented as

The solubility equilibrium of AgBr is represented as

Now the product of

can not exceed 5 x 10^-13 mol² L^-2

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