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Methyl Ketones CH 3 COR on oxidation with X 2 /NaOH (X = Cl, Br, I) gives sodium salt of carboxylic acid with one carbon atom less. The CH 3 group bonded to carbonyl group is converted to haloform, CHX 3 '. With iodine in NaOH, a yellow precipitate of iodoform CHI 3 is obtained (iodoform test).

Explain haloform reaction.

Methyl Ketones CH₃COR on oxidation with X₂/NaOH (X = Cl, Br, I) gives sodium salt of carboxylic acid with one carbon atom less. The CH₃ group bonded to carbonyl group is converted to haloform, CHX₃'. With iodine in NaOH, a yellow precipitate of iodoform CHI₃ is obtained (iodoform test).

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