The density (in g mL^–1) of a 3.60 M sulphuric acid solution that is 29% H₂SO₄ (Molar mass = 98 g mol^-) by mass will be 

• 1.64

• 1.88

• 1.22

• 1.22

C.

1.22

Let the density of solution be ‘d’
Molarity of solution given = 3.6
i.e. 1 litre of solution contains 3.6 moles of H₂SO₄
or 1 litre of solution contains 3.6 × 98 gms of H₂SO₄
Since, the solution is 29% by mass.
100 gm solution contains 29 gm H₂SO₄
100/d ml l  solution contains 29 gm of H₂SO₄.
1000 ml solution contains 3.6 × 98 gm of H₂SO₄

d = 1.22