Solve the following pair of linear equations by the elimination method and the substitution method3x – 5y – 4 = 0 and 9x = 2y + 7 - Zigya
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Solve the following pair of linear equations by the elimination method and the substitution method
3x – 5y – 4 = 0 and 9x = 2y + 7


3x - 5y = 4    ...(i)
9x - 2y = 7    ...(ii)
For making the coefficient of x in (i) and (ii) equal, we multiply eqn. (i) by 3 and subtracting, we get
   9x - 15y = 12
   9x - 2y = 7
  -    +        -
-13y    = 5
rightwards double arrow fraction numerator negative 5 over denominator 13 end fraction
Now putting the value of y in (i), we get

bottom enclose space space space space space space space space space space 3 straight x space minus space 5 straight y space equals end enclose space 4
rightwards double arrow space 3 straight x minus 5 open parentheses fraction numerator negative 5 over denominator 13 end fraction close parentheses space equals space 4
rightwards double arrow space 3 straight x plus 25 over 13 space equals space 4
rightwards double arrow space 3 straight x equals 4 over 1 minus 25 over 13
rightwards double arrow space space 3 straight x space equals space fraction numerator 52 minus 25 over denominator 13 end fraction
rightwards double arrow space 3 straight x space equals space 27 over 13
rightwards double arrow space space space space space straight x space equals space 9 over 13
Hence comma space space straight x equals space 9 over 13 comma space space straight y space equals space fraction numerator negative 5 over denominator 13 end fraction

Substitution method :
We have,
3x - 5y = 4    ...(i)
9x - 2y = 7    ...(ii)
From (i), we have
3x - 5y = 4

rightwards double arrow space space 3 straight x space equals space 4 space plus space 5 straight y
rightwards double arrow space space space straight x space equals space fraction numerator 4 plus 5 straight y over denominator 3 end fraction space space space space space space... left parenthesis iii right parenthesis
Substituting the value of (iii) in (ii), we get

3x - 5y = 4    ...(i)9x - 2y = 7    ...(ii)For making the coeff
Now, substituting the value ofy in (iii), we get

3x - 5y = 4    ...(i)9x - 2y = 7    ...(ii)For making the coeff



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