For which value of k will the following pair of linear equations have no solution?
3x + y = 1 (2k – 1) x + (k – 1) y = 2k + 1

The given pair of linear equations is
3x + y = 1
(2k - 1) x + (k - 1) y= 2k + 1
⇒ 3x + y - 1 = 0
Here, (2k - 1) x + (k - 1) y - (2k + 1) = 0
a₁ = 3, b₁ = 1, c₁ = -1)
a₂ = 2 k - 1, b₂ = k - 1 c₂ = - (2k + 1)
For having no solution, we must have