A chord of a circle of radius 14 cm subtends 60° at the centre. Find the area of the major sector.

Here, r = 14 cm and ∠AOB = 60°

therefore

Area of major sector = Area of the circle - Area of minor sector

equals space πr squared minus fraction numerator 60 degree over denominator 360 degree end fraction xπr squared equals space open parentheses 1 minus 1 over 6 close parentheses space πr squared equals space 5 over 6 straight x 22 over 7 straight x space 14 space straight x space 14 space cm squared equals space 1540 over 3 equals 513 1 third space cm squared

Here, r = 14 cm and ∠AOB = 60° Area of major sector = Area of the

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