For what value of k will k+9, 2k-1 and 2k+7 are the consecutive terms of an A.P?
If k+9, 2k-1 and 2k+7 are the consecutive terms of A.P, then the common difference will be the same. ∴ (2k – 1) – (k + 9) = (2k + 7) – (2k – 1)
∴ k – 10 = 8
∴ k = 18
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