Three different coins are tossed together. Find the probability of getting
(i) exactly two heads
(ii) at least two heads
(iii) at least two tails.

When three coins are tossed together, the possible outcomes are
HHH, HTH, HHT, THH, THT, TTH, HTT, TTT
therefore,
Total number of possible outcomes = 8

(i) Favourable outcomes of exactly two heads are HTH, HHT, THH
Total number of favourable outcomes= 3
Probability of getting exactly two heads = 3/8

(ii) Favourable outcomes of at least two heads are HHH, HTH, HHT, THH
Total number of favourable outcomes =4
Probability of getting at least two heads =4/8 = 1/2


(iii)Favourable outcomes of at least two tails are THT, TTH, HTT, TTT
Total number of favourable outcomes =4
Probability of getting at least two tails - 4/8 = 1/2