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If P, Q, R, S are the points (– 2, 3, 4), (– 4, 4, 6), (4, 3, 5), (0, 1, 2), prove by projection that PQ is perpendicular to RS.


The given points are P (– 2, 3, 4), Q (– 4, 4, 6), R (4, 3, 5) and S (0, 1, 2).
Direction ratios of RS are. 0 – 4, 1 – 3, 2 – 5 i.e., – 4, – 2, – 3
∴    direction-cosines of RS are
     negative fraction numerator 4 over denominator square root of 16 plus 4 plus 9 end root end fraction comma space space minus fraction numerator 2 over denominator square root of 16 plus 4 plus 9 end root end fraction comma space minus fraction numerator 3 over denominator square root of 16 plus 4 plus 9 end root end fraction space space space straight i. straight e. comma space space minus fraction numerator 4 over denominator square root of 29 end fraction comma space minus fraction numerator 2 over denominator square root of 29 end fraction comma space minus fraction numerator 3 over denominator square root of 29 end fraction
therefore       projection of PQ on RS
                              equals space open square brackets negative 4 minus left parenthesis negative 2 right parenthesis close square brackets space space space open parentheses negative fraction numerator 4 over denominator square root of 29 end fraction close parentheses plus left parenthesis 4 minus 3 right parenthesis space open parentheses negative fraction numerator 2 over denominator square root of 29 end fraction close parentheses plus left parenthesis 6 minus 4 right parenthesis space open parentheses negative fraction numerator 3 over denominator square root of 29 end fraction close parentheses

                                                                  open square brackets because space space space of space space space left parenthesis straight x subscript 2 minus straight x subscript 1 right parenthesis space straight l space plus space left parenthesis straight y subscript 2 minus straight y subscript 1 right parenthesis space straight m space plus space left parenthesis straight z subscript 2 minus straight z subscript 1 right parenthesis space straight n close square brackets
                                equals space left parenthesis negative 2 right parenthesis space open parentheses negative fraction numerator 4 over denominator square root of 29 end fraction close parentheses plus left parenthesis 1 right parenthesis space open parentheses negative fraction numerator 2 over denominator square root of 29 end fraction close parentheses plus left parenthesis 2 right parenthesis space open parentheses negative fraction numerator 3 over denominator square root of 29 end fraction close parentheses
equals fraction numerator 8 over denominator square root of 29 end fraction minus fraction numerator 2 over denominator square root of 29 end fraction minus fraction numerator 6 over denominator square root of 29 end fraction equals 0

∴ PQ is perpendicular to RS.
[∵ projection of a line perpendicular to it is zero]

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