If xm yn = (x + y)m + n, prove that
We are given,
If xm yn = (x + y)m + n
Taking log on both sides, we get
log xm yn = log(x + y)m + n
log xm + log yn = m+n log(x + y)
m logx + n logy = m+n log (x+y)
Differentiating above equation w.r.t. x, we get