A 5 m 60 cm high vertical pole casts a shadow 3 m 20 cm long. Find at the same time (i) the length of the shadow cast by another pole 10 m 50 cm high and (ii) the height of a pole which casts a shadow 5 m long.
Solution: (i) Let the required length of shadow be x cm.
|
Height of the pole |
Length of the shadow |
|
5 m 60 cm = 560 cm |
3 m 20 cm = 320 cm |
As the height of the pole increases the length of its shadow also increases in the same ratio. Therefore, it is a case of direct variation.
(ii) Let the required height of the pole be y cm.
∴ We have:
|
Height of the pole |
Length of the shadow |
|
560 cm y |
320 cm 5 m = 500 cm |
