An object 2 cm in size is placed 30 cm in front of a concave mirror of focal length 15 cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image? What will be the nature and the size of the image formed? Draw a ray diagram to show the formation of the image in this case. - Zigya
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An object 2 cm in size is placed 30 cm in front of a concave mirror of focal length 15 cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image? What will be the nature and the size of the image formed? Draw a ray diagram to show the formation of the image in this case.


Here,   h = + 2 cm,   u = - 30 cm,   f = -15 cm
As               1 over straight u plus 1 over straight v space equals 1 over straight f
therefore        1 over straight v space equals space 1 over straight f minus 1 over straight u space equals space fraction numerator 1 over denominator negative 15 end fraction minus fraction numerator 1 over denominator negative 30 end fraction space equals space minus 1 over 30
or                                  straight v space equals space minus 30 space cm. space space space Ans. space
Thus, the screen should placed at 30 cm in front of the mirror so as to obtain the real image.
Magnification,  straight m space equals space fraction numerator straight h apostrophe over denominator straight h end fraction space equals space minus straight v over straight u
Image size,  h' = negative vh over straight u space equals space minus fraction numerator left parenthesis negative 30 right parenthesis space left parenthesis plus 2 right parenthesis over denominator left parenthesis negative 30 right parenthesis end fraction space equals space minus space 2 space cm
The image is real, inverted and of the same size as the object. The image formation is shown in the ray diagram given below.

Here,   h = + 2 cm,   u = - 30 cm,   f = -15 cmAs           ?


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