A ring is rolling on a horizontal surface without slipping. Find the ratio of translation kinetic energy to rotational kinetic energy of ring. - Zigya
Advertisement

A ring is rolling on a horizontal surface without slipping. Find the ratio of translation kinetic energy to rotational kinetic energy of ring.


Let m be the mass and r be the radius of ring.

When the ring rolls without slipping, then v = rω,

where v is the velocity of centre of mass of ring, and
ω is its angular velocity.

Now the translational kinetic energy of the ring is,

straight K subscript straight t space equals space 1 half mv squared space

space space space space equals 1 half mr squared straight ϖ squared space

Rotational kinetic energy of the ring is,

straight K subscript straight r space equals 1 half Iϖ to the power of 2 space end exponent
space space space space space equals space 1 half mr squared straight ϖ squared

Therefore comma space the space ratio space o f space translational space to space rotational
straight K. straight E space is space given space by comma space

therefore space space straight K subscript t over straight K subscript r equals 1

840 Views

Advertisement

System of Particles and Rotational Motion

Hope you found this question and answer to be good. Find many more questions on System of Particles and Rotational Motion with answers for your assignments and practice.

Physics Part I

Browse through more topics from Physics Part I for questions and snapshot.