Plot the graph for the variation of kinetic energy, potential energy and total energy with displacement of particle executing simple harmonic motion.

Kinetic energy

$straight K equals 1 half mω squared left parenthesis straight A squared minus straight y squared right parenthesis equals 1 half mω squared straight A squared minus 1 half mω squared straight y squared$

Kinetic energyTherefore the graph for kinetic energy versus displacem

Therefore the graph for kinetic energy versus displacement is a parabola. Potential energy:

$straight U equals 1 half mω squared straight y squared$

The graph for potential energy versus displacement is also parabola. Total energy:

$straight E equals straight K plus straight U equals 1 half mω squared straight A squared$
Graph is straight line parallel to displacement axis.

602 Views

Oscillations

Hope you found this question and answer to be good. Find many more questions on Oscillations with answers for your assignments and practice.

Physics Part II

Browse through more topics from Physics Part II for questions and snapshot.