A spherical conducting shell of inner radius r1 and outer radius r2 has a charge Q.i) A charge q is placed at the centre of the shell. What is the surface charge density on the inner and outer surfaces of the shell?ii) Is the electric field inside a cavity (with no charge) zero, even if the shell is not spherical, but has any irregular shape? Explain. - Zigya
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A spherical conducting shell of inner radius r1 and outer radius r2 has a charge Q.
i) A charge q is placed at the centre of the shell. What is the surface charge density on the inner and outer surfaces of the shell?
ii) Is the electric field inside a cavity (with no charge) zero, even if the shell is not spherical, but has any irregular shape? Explain.


As a ‘+ q’ charge place at the centre of the shell, it will create a ‘–q’ charge on the inner surface of the shell.
The charge on the outer surface will increase by + q due to the –q charge on the inner surface by induction. Therefore, there will be total (Q + q) charge on the outer surface of the shell and –q charge on the inner surface of the shell.

As a ‘+ q’ charge place at the centre of the shell, it will creat
Now surface area of inner surface space equals space 4 πr subscript 1 squared
and surface area of outer surface space equals space 4 πr subscript 2 squared
Thus, charge density on the outer surface  space equals space fraction numerator straight Q plus straight q over denominator 4 πr subscript 2 squared end fraction
and charge density on the inner surface space equals space fraction numerator negative straight q over denominator 4 πr subscript 1 squared end fraction.

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