The electric field E due to a point charge at any point near it is defined as $E = \lim_{q \to 0} \frac{F}{q},$ where q is the test charge and F is the force acting on it. What is the physical significance of $\lim_{q \to 0}$ in this expression? Draw the electric field lines of a point charge Q when (i) Q > 0 and (ii) Q < 0

It is indicated by the

limit as straight q rightwards arrow 0 of

that the test charge q is so small that its presence does not disturb the distribution of source charge and therefore, its electric field. The electric fields of the point charge Q are shown below.
It is indicated by the that the test charge q is so small that i

It is indicated by the that the test charge q is so small that i

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The electric field E due to a point charge at any point near it is defined as E = limq→0Fq, where q is the test charge and F is the force acting on it. What is the physical significance of limq→0 in this expression? Draw the electric field lines of a point charge Q when (i) Q > 0 and (ii) Q < 0

Electric Charges and Fields

Physics Part I