Show that a bubbled OR gate is equivalent to a NAND gate. Hence prove the identity.

A bubbled OR gate is the combination of two NOT gates and one OR gate. That is, the output of two NOT gates is made as input of OR gate.

The Boolean expression for output of this gate is

Y = \bar{A} + \bar{B} = \bar{A . B}

(From De-Morgan’s Theorem).

This expression represents NAND gate.

Hence, a bubbled OR gate is equivalent to a NAND gate.

656 Views

Semiconductor Electronics: Materials, Devices and Simple Circuits

Hope you found this question and answer to be good. Find many more questions on Semiconductor Electronics: Materials, Devices and Simple Circuits with answers for your assignments and practice.

Physics Part II

Browse through more topics from Physics Part II for questions and snapshot.