A rectangular coil of length 0.12 m and width 0.1 m having turns of wire is suspended vertically in a uniform magnetic field of strength 0.2 Wb/m2.The coil carries a current of 2 A. If the plane of the coil is inclined at an angle of 30o with the direction of the field, the torque required to keep the coil in stable equilibrium will be
0.15 Nm
0.20 Nm
0.24 Nm
0.24 Nm
B.
0.20 Nm
Given N = 50
B = 0.2 Wb/m2, I = 2A
θ = 60o, A = 0.12 x 0.1 = 0.012 m2
= NIAB sin θ = 50 x 2 x 0.012 x0.2 sin 60o
