In a region, the potential is represented by V (x,y,z) = 6x - 8 xy - 8y + 6yz, where V is in volts and x, y, z are in metres. The electric force experienced by a charge of 2 coulomb situated at point (1,1,1) is,
6√5 N
30 N
24 N
24 N
D.
24 N
We know,
F = qE ... (i)
E = ... (ii)
The values of Ex, Ey and Ez at (1,1,1) are
Ex = 6 - 8x(1) = -2
Ey = -8(1) - 8 + 6(1) = -10
Ez = 6 x 1 = 6
Therefore,