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Find the cube root of each of the following numbers by prime factorisation method.

(ix) 175616


(ix) By prime factorisation, we have


(ix) By prime factorisation, we have     175616   =  2 x 2 x 2 x

     175616   =  2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 7 x 7 x 7

                   = 2 x 2 x 2 x 7 = 56

Thus, the cube root of 175616 is 56



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Find the cube root of each of the following numbers by prime factorisation method.

(viii) 46656


(viii) By prime factorisation, we have


(viii) By prime factorisation, we have46656  = 2 x 2 x 2 x 2 x 2 x 2

46656  = 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3 x 3 x 3 x 3

∴   cube root of 46656 space equals space2 x 2 x 3 x 3 = 36

Thus, the cube root of 46656 is 32






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Find the cube root of each of the following numbers by prime factorisation method.

(x) 91125


(ix) By prime factorisation, we have

91125  = 3 x 3 x 3 x 3 x 3 x 3 x 5 x 5 x 5

∴   cube root of 91125 space equals 3 x 3 x 5 = 45

Thus, the cube root of 91125 is 45.



     
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State true or false

  • (i) Cube of any odd number is even.

  • (ii) A perfect cube does not end with two zeros

  • (iii) If square of a number ends with 5, then its cube ends with 25.

  • (iii) If square of a number ends with 5, then its cube ends with 25.

  • (iii) If square of a number ends with 5, then its cube ends with 25.

  • (vi) The cube of a two digit number may have seven or more digits.

  • (vii) The cube of a single digit number may be a single digit number.


B.

(ii) A perfect cube does not end with two zeros

G.

(vii) The cube of a single digit number may be a single digit number.

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Find the cube root of each of the following numbers by prime factorisation method.

(vii) 110592


(vii) By prime factorisation, we have


(vii) By prime factorisation, we have110592 = 2 x 2 x 2 x 2 x 2 x 2 x

110592 = 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 2 x 3 x 3 x 3

∴   cube root of 110592 space equals space2 x 2 x 2 x 2 x 3 = 48

Thus,  the cube  root of 110592  is 48







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