Write the following sets in the roster form :
(i) A = {jt : x ∊ Z and x is a root of the quadratic equation x2 - 3x - 10 = 0}
(ii) B = {x : x ∊ N, -5 < x - 2 < 5}
(iii) C = {x : jc is an odd prime number less than 30}
(i) A = and x is a root of quadratic equation x2 -3x -10 = 0}
Now, x2 -3x -10 = 0 (x-5) (x+2) = 0
x=5, -2 which are both integers.
Hence, A = {-2, 5}
(ii) B= {x :x , -5 < x-2 < 5}
Now, -5 < x-2 < 5 -3 < x < 7
x is a natural number between -3 and 7 (exclusive).
Hence, B = {1, 2, 3, 4, 5, 6}
(iii) C = {x : x is an odd prime number less than 30} x = 3, 5, 7, 11, 13, 17, 19, 23, 29
Hence C = { 3, 5, 7, 11, 13, 17, 19, 23, 29}
If A ⊆ B, show that:
(a) A ∩ B=A (b) A ∪ B = B
(a)
Hence, A
(b) x = (-1)-1 .1, (-1)2 . 2, (-1)3 . 3, (-1)4 .4, (-1)5 .5
= -1, 2, -3, 4, -5
Hence, B = {-1, 2, -3, 4, -5}