Use ruler and compasses only for this question
I. Construct ABC, where AB = 3.5 cm, BC = 6 cm and
II. Construct the locus of points inside the triangle which are equidistant from BA and BC.
III. Construct the locus of points inside the triangle which are equidistant from B and C.
IV. Mark the point P which is equidistant from AB, BC and also equidistant from B and C. Measure and record the length of PB.
Steps of constructions:
(i) Draw a line BC = 6 cm and . Cut off AB = 3.5 cm. Join AC, is the required triangle.
(ii) Draw perpendicular bisector of BC and bisector of B.
(iii) Bisector of B meets bisector of BC at P, therefore BP is the required length, Where BP = 3.5 cm.
(iv) P is the point which is equidistant from BA and BC, also equidistant from B and C.
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