Capacitors each of capacitance C.
Series capacitance = Cs.
Parallel capacitance = Cp.
Cp= C + C + C = 3C
An isolated 16 μF parallel plate air capacitor has a potential differences of 1000 V (Figure 5 a). A dielectric slab having relative permittivity (i.e. dielectric constant) = 5 is introduced to fill the space between the two plates com pletely. (Figure 5 b). Calculate:
(i) The new capacitance of the capacitor.
(ii) The new potential differences between the two plates of the capacitor
C1 = 16 μ F where C1 → Capacitance of figure 5(a)
V1= 1000 V C2 → Capacitance of figure 5 (b)
(i) C2 / C1 = K
C2 = K C1
= 5 X 16
= 80 μF, is the new capacitance of the capacitor.
(ii) Similarly V2 / V1 = 1/K
V2 = V1 / K
= 1000 / 5
= 200 V.
a) Obtain an expression for equivalent capacitance when three capacitors C1, C2 and C3 are connected in series.
b) A metallic wire has a resistance of 3.0 ohm and 0o Cand 4.8 ohm at 150o C. Find the temperature coefficient of resistance of its material?
Three capacitors C1 = 6μF,C2 = 12μF and C3 = 20μF are connected to a 100 V battery, as shown in Figure 2 below :
Calculate:
(i) Charge on each plate of capacitor Cx
ii) Electrostatic potential energy stored in capacitor C3.
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