Show the following data by means of a suitable diagram.
Production of Tea, Cocoa, Coffee
|
Tea |
3260 tons |
|
Cocos |
1850 tons |
|
Coffee |
900 tons |
|
Total |
6010 tons |
|
Product |
Production |
Pecentage |
Angle in Degrees |
|
Tea |
3260 |
|
54.26 × 3.6 = 195° |
|
Cocoa |
1850 |
|
30.78 × 3.6 = 1110 |
|
Coffee |
900 |
|
14.975 × 3.6 = 54° |
Explain the objectives of tabulation.
Following are the objectives of tabulation:
1. In tabulation the data are presented systematically in columns and rows in a concise form. Thus, data becomes more meaningful and lot of time is saved in its study and understanding.
2. When the data are arranged in tables with titles and table number, they can be easily identified and made use of a source reference for future studies.
3. Tabulation of data shows the trend of the information under study and depicts the patterns with in the figures which cannot be understood in a descriptive form of presentation.
4. It is only after tabulation that data becomes fit for statistical processing.
Give purposes of classification.
Following are the objectives (purposes) of classification:
1. To condense the mass of data in such a manner that similarities and dissimilarities are reedily apprehended and relationships studies.
2. To facilitate comparisons.
3. To have a bird’s eye-view of the significant feature of the data.
4. To englight important information while giving less prominence to insignificant items.
5. To utilise the data for tabulation and further statistical analysis.
6. To eliminate unnecessary details contained in the raw data.
7. To present the complex, scattered in a concise, logical and understable form.
Draw less than cumulative frequency curve with the help of following frequency distribution :
|
Marks in Maths |
No. of Students |
|
0 – 20 |
6 |
|
20 – 40 |
5 |
|
40 – 60 |
33 |
|
60 – 80 |
14 |
|
80 – 100 |
6 |
|
Total |
64 |
|
Marks in Maths |
No. of Students (f) |
“Less than” Cumulative Frequency |
|
0 – 20 |
6 |
6 |
|
20 – 40 |
5 |
11 |
|
40 – 60 |
33 |
44 |
|
60 – 80 |
14 |
58 |
|
80 – 100 |
6 |
64 |
|
64 |
We have to draw a histogram with the help of following data. What amendment will be make in class intervals for doing so?
|
Weight (in kg.) Class interval |
No. of Students frequencies (f) |
|
10 – 19 |
4 |
|
20 – 29 |
12 |
|
30–39 |
15 |
|
40 – 49 |
20 |
|
50 – 59 |
10 |
|
60 – 69 |
5 |
Here the series is not continuous. Hence, we have to make it continuous for doing so, we will divide the difference of class boundaries by 2. The resultant figure i.e. 5 by be deducted from the lower limit and added in the upper limit. Hence:
|
Weight (in kg.) Class interval |
No. of Students frequencies (f) |
|
9.5 – 19.5 |
4 |
|
19.5 – 29.5 |
12 |
|
29.5 – 39.5 |
15 |
|
39.5 – 49.5 |
20 |
|
49.5 – 59.5 |
10 |
|
59.5 – 69.5 |
5 |
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