Find the equation of tangents to the curve y= x3+2x-4, which are perpendicular to line x+14y+3 =0.
Taking the given equation,
y = x3+2x-4
Differentiating the above function with respect to x, we have,
Given that the tangents to the given curve are perpendicular to the line x+ 14y + 3 = 0
Slope of this line, m2=-1/14
Since the given line and the tangents to the curve are perpendicular, we have,
m1 x m2 =-1
thus equation of the tangent is 14 x- y =-12
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