Write the following in the usual form.
(i) 10 x 5 + 6 (ii) 100 x 7 + 10 x 1 + 8 (iii) 100 x a + 10 x c + b
(i) 10 x 5 + 6 = 50 + 6 = 56
(ii) 100 x 7 + 10 x 1 + 8 = 700 + 10 + 8 = 718
(iii) 100 x a + 10 x c + b = 100 a + 10c + b = ![<pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
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Check what the result would have been if Minakshi had chosen the numbers shown below. In each case keep a record of the quotient obtained at the end.
1. 132 Chosen number = 132
Reversed number = 231
Difference = 231 - 132
= 99
We have 99 + 99 = 1, remainder = 0
2. 469 Chosen number = 469
Reversed number = 964
Difference = 964 - 469 = 495
We have 495 + 99 = 5, remainder = 0
3. Chosen number = 737
Reversed number = 737
We have dirrerence = 737 - 737 = 0
0 + 99 = 0, remainder = 0
4. Chosen number = 901
Reversed number = 109
Differende = 901 - 109
= 792
We have 792 + 99 = 8, remainder = 0
Forming three digit number with given three dgits.
Write the following numbers in generalized form.
(i) 25 (ii) 73 (iii) 129 (iv) 302
(i) 25 = 20 + 5
= 10 x 2 + 5 x 1 = 10 x 2 + 5
(ii) 73 = 70 + 3
= 10 x 7 + 3 x 1 = 10 x 7 + 3
(iii) 129 = 100 + 20 + 9
= 100 x 1 + 20 x 2 + 1 x 9 = 100 x 1 + 10 x 2 + 9
(iv) 302 = 100 x 3 + 10 x 0 + 1 x 2 = 300 + 0 + 2
Check what the result would have been if sundaram had chosen the numbers shown below. 1. 27 2. 39 3. 64 4. 17
1. Chosen number = 27
Number with reversed digits = 72
Sum of the two numbers = 27 + 72 = 99
Now, 99 = 11[9]
= 11[2 + 7]
= 11(Sum of the digits of the chosen number)
2. Chosen number = 39
Number with reversed digits = 93
Sum of the two numbers = 39 + 93 = 132
Now, 132 + 11 = 12
i,e, 132 = 11[12]
= 11 [ 3 + 9]
= 11 [ Sum of the digits of the chosen number]
3. Chosen number = 64
Number with reversed digits = 46
Sum = 64 + 46 = 110
Now, 110 = 11[10]
= 11[6 + 4]
= 11[ Sum of the digits of the chosen number
4. Chosen number = 17
Number with reversed digits = 71
Sum = 17 + 71 = 88
Now, 88 = 11[8]
= 11[1+7]
= 11[Sum of the digits of the chosen number]
Check what result would have been if Sundaram had chosen the numbers shown. 1.17 2.21 3.96 4.37.
1. Chosen number = 17
Number with reversed digits = 71
Difference = 71 - 17 = 54
= 9 x [6]
2. Chosen number = 21
Number with reversed digits = 12
Difference = 21 - 12 = 9
= 9 x [1]
= 9 x [Difference between the digits of the chosen number (2 - 1 = 1)]
3. Chosen number = 96
Number with reversed digits = 69
Difference = 96 - 69 = 27
= 9 x [3]
= 9 x [Difference between the digits of the chosen number (9 - 6)]
4. Chosen number = 37
Number with reversed digits = 73
Difference = 73 - 37 = 36
= 9 x [4]
= 9 x [Difference between the digits of the chosen number (7 - 3 = 4)]
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