Let a be the length of an edge of the cube. Then
a = 7 cm
Greatest diameter of the hemisphere
= Length of an edge of the cube
= 7 cm
Now,
Surface area of the cube
= 6 (edge)2
= 6 x 72
= 6 x 49 = 294 cm2
Let r be the radius of the hemisphere.
Then, r =
Now,
Curbed surface area of hemisphere
And, Base area =
Total surface area
= Surface area of the cube + curved surface area of the hemisphere – base area of the hemisphere
It is given that,
Edge of the cube = l
Then, Surface area = 6 (edge)2 = 6l2
Now, the greatest diameter of hemisphere
= length of an edge of the cube
= l
So, curved surface area of the hemisphere
And, Area of base of the hemisphere
Required surface area
= Surface area of the cubical wooden block – area of the base of the hemisphere + curved surface area of the hemisphere
Let ‘a’ be the length of a side of a cube. Then
Volume of one cube = 64 cm3
⇒ n3 = 65 cm3
⇒ n = 4 cm
On joining the cubes, a cuboid is formed.
Then The length of the resulting cuboid (l) = 2
The breadth of the resulting cuboid (b) = a cm
The thickness of the resulting cuboid (h) = a cm
Now,
Surface area of the resulting cuboid
= 2(lb + bh + hl)
= 2 (2a. a + a. a + a. 2a)
= 2 (2a2 + a2 + 2a2)
= 2 (5a2) = 10a2 = 10 (4)2
= 160 cm2.
r = 3.5 cm,
h = (15.5 – 3.5) cm = 12 cm.
Now, l =
Let r cm be the radius of the cylinder and h cm be the height of the cylinder, then
r = 7 cm,
and h = (13–7) cm
= 6 cm.
Let r1 cm be the radius of the hemisphere, then
r1 = 7 cm
Now,
the inner curved surface area of the vessel
= C,S.A of hemisphere
+ C,S.A of cylinder
= (2πr12 + 2 π rh) cm2
= (2 π r2 + 2 π rh) cm2 [∵ r1 = r]
= [2 π r (r + h)] cm2
= (44 x 13) cm2
= 572 cm2.