Galvanization is applying a coating of: from Chemistry Electroc
straight a right parenthesis space space Calculate space straight E subscript cell superscript 0 space for space the space following space reaction space at space 298 space straight K colon
2 Al left parenthesis straight s right parenthesis space plus 3 Cu to the power of 2 plus end exponent left parenthesis 0.01 space straight M right parenthesis space rightwards arrow 2 Al to the power of 3 plus end exponent space left parenthesis 0.01 straight M right parenthesis space plus 3 Cu left parenthesis straight s right parenthesis
Given space colon space straight E subscript cell space equals space 1.98 space straight V
straight b right parenthesis space using space the space straight E to the power of 0 space values space of space straight A space and space straight B space predict space which space is space better space for space coating space the space surface space of space iron space left square bracket straight E to the power of 0 left parenthesis Fe to the power of 2 plus end exponent divided by Fe right parenthesis
equals negative 0.44 straight V right square bracket space to space prevent space corrosion space and space why ?
Given space colon space straight E to the power of 0 left parenthesis straight A to the power of 2 plus end exponent divided by straight A right parenthesis space equals space minus 2.37 space colon space straight E to the power of 0 left parenthesis straight B to the power of 2 plus end exponent divided by straight B right parenthesis space equals negative 0.14 space straight V

OR
straight a right parenthesis space The space conductivity space of space 0.001 space mol space straight L to the power of negative 1 end exponent space solution space of space CH subscript 3 COOH space space is space 3.905 space straight x space 10 to the power of negative 5 end exponent space straight S space cm to the power of negative 1 end exponent. space
Calculate space its space molar space conductivty space and space degree space of space dissociation space left parenthesis straight alpha right parenthesis

Given space straight lambda to the power of 0 space left parenthesis straight H to the power of plus right parenthesis space equals 349.6 space straight S space Cm squared space mol to the power of negative 1 end exponent space and space straight lambda to the power of 0 space left parenthesis CH subscript 3 COO to the power of minus right parenthesis space equals space 40.9 space straight S space cm squared space mol to the power of negative 1 end exponent

straight b right parenthesis space Define space electrochemical space cell space what space happen space if space external space potential space applied space
becomes space greater space than space straight E subscript cell superscript 0 space of space electrochemical space cell.

a)


b) A is better for coating the surface of the iron because its E0  value is more negative.


Or

a) 

b) A device used for the production of electricity from energy released during the spontaneous chemical reaction and the use of electrical energy to bring about a chemical change. The reaction gets reversed /  It starts acting as an electrolytic cell & vice – verse.

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Galvanization is applying a coating of:

  • Cr

  • Cu

  • Zn

  • Zn


C.

Zn

Zinc metal is the most stable metal to cover iron surfaces. The process of coating the iron surface by zinc is called galvanization.

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(a) What type of a battery is lead storage battery? Write the anode and cathode reactions and the overall cell reaction occurring in the operation of a lead storage battery.

(b) Calculate the potential for half-cell containing 0.10 M K2Cr2O7 (aq), 0.20 M Cr3+(aq) and 1.0 x 10-4 M H+ (aq)

The half-cell reaction is Cr subscript 2 straight O subscript 7 superscript 2 minus end superscript left parenthesis aq right parenthesis straight space plus straight space 14 straight space straight H to the power of plus subscript left parenthesis aq right parenthesis end subscript straight space plus straight space 6 straight e to the power of minus straight space rightwards arrow straight space 2 Cr subscript left parenthesis aq right parenthesis end subscript superscript 3 plus end superscript straight space plus straight space 7 straight H subscript 2 straight O subscript left parenthesis straight l right parenthesis end subscript

And the standard electrode potential is given as E0 = 1.33 V.

 OR

(a) How many moles of mercury will be produced by electrolysing 1.0 M?

Hg (NO3)2 solution with a current of 2.00 A for 3 hours?

[Hg (NO3)2 = 200.6 g mol-1]

(b) A voltaic cell is set up at 25°C with the following half-cells Al3+ (0.001 M) and Ni2+ (0.50 M). Write an equation for the reaction that occurs when the cell generates an electric current and determine the cell potential.

 Error converting from MathML to accessible text.


(a) A lead storage battery is a secondary battery.

The following chemical equations take place in a lead storage battery.


When a battery is charged, the reverse of all these reactions takes place.

Hence, on charging, PbSO4(s) present at the anode and cathode is converted into Pb(s) and PbO2(s) respectively.

b) 
Or

(a) Quantity of electricity passed = (2A) x (3 x 60 x 60s) = 21600 C

Thus, 2F i.e. 2 x 96500 C deposit Hg = 1 mole 21600 C will deposit Hg

 

= 0.11 mole

Or

At anode:             Al (s)                  -->     Al3+ (aq) + 3e-] x2

At cathode:          Ni2+ + 2e-               -->   Ni(s)                ] x3

Cell reaction:     2Al(s) + 3Ni2+(aq) --->   2Al3+(aq)  + 3Ni (s)

Applying nernst equation to the above cell reaction 


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Two Faraday of electricity is passed through a solution of CuSO4. The mass of copper deposited at the cathode is: (at. mass of Cu = 63.5 amu)

  • 0 g

  • 63.5 g

  • 2 g

  • 2 g


B.

63.5 g

Atomic mass of Cu = 63.5 u
Valency of the metal Z= 2
We have,
CuSO4 → Cu2+ + SO42-
Cu2+ + 2e-  →  Cu

1 mol   2 mol       1 mol = 63.5 g
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Which among the following metals is employed to provide cathodic protection to iron?

  • Zinc

  • Nickel

  • Tin

  • Lead


A.

Zinc

Cathodic protection of iron involves using another more reactive metal or a sacrificial anode. Since, in electrochemical series, Zn is placed above Fe, so it is used for such action.


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