In the matrix (i) The order of the matrix(ii) The number of ele
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If a matrix has 18 elements, what are the possible orders it can have? What, if it has 5 elements?


We know that a matrix of order m x n has mnelements. Therefore, for finding all possible orders of a matrix with 18 elements, we will find all ordered pairs with products of elements as 18
∴ all possible ordered pairs areall possible ordered pairs areall possible ordered pairs areall possible ordered pairs areall possible ordered pairs areall possible ordered pairs are  (I, 18). (18, 1). (2, 9). (9. 2). (3, 6). (0, 3)
∴ possible orders are 1 x 18. 18 x 1. 2 x 9,-9 X 2, 3 x 6. 6 x 3.
If number of elements = 5, then possible orders arc 1 x 5. 5 x I.

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Construct a 2 x 2 matrix, A = [ai j], whose elements are given by :
straight a subscript ij equals fraction numerator left parenthesis straight i plus straight j right parenthesis squared over denominator 2 end fraction

 A = [ai j] is 2 x 2 matrix where , aijfraction numerator left parenthesis straight i plus straight j right parenthesis squared over denominator 2 end fraction
therefore space space space space straight a subscript 11 equals fraction numerator left parenthesis 1 plus 1 right parenthesis squared over denominator 2 end fraction equals 4 over 2 equals 2 space space space space space space space space space space space space space space space space space straight a subscript 12 equals fraction numerator left parenthesis 1 plus 2 right parenthesis squared over denominator 2 end fraction equals 9 over 2
space space space space space space space straight a subscript 21 equals fraction numerator left parenthesis 2 plus 1 right parenthesis squared over denominator 2 end fraction equals 9 over 2 space space space space space space space space space space space space space space space space space space space space space straight a subscript 23 equals fraction numerator left parenthesis 2 plus 2 right parenthesis squared over denominator 2 end fraction equals 16 over 2 equals 8
therefore space space space space straight A equals open square brackets table row 2 cell 9 over 2 end cell row cell 9 over 2 end cell 8 end table close square brackets

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If a matrix has 24 elements, what are the possible orders it can have? What, if it has 13 elements?


We know that a matrix of order m x n has mn elements. Therefore, for finding all possible orders of a matrix with 24 elements, w e will find all ordered pairs with products of elements as 24.
∴ all possible ordered pairs are
(1, 24), (24. 1), (2, 12), (12. 2). (3, 8), (8, 3), (4. 6), (6, 4)
∴ possible orders are
1 x 24. 24 x 1, 2 x 12, 12 x 2, 3 x 8, 8 x 3, 4 x 6. 6 x 4
If number of elements  =13, then possible orders are 1 x 13, 13 x l.

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Construct a 2 x 2 matrix, A = [ai j], whose elements are given by :
straight a subscript ij equals i over j

A = [aij] is 2 x 2 matrix where aijstraight i over straight j
therefore space space straight a subscript 11 equals 1 over 1 equals 1 comma space space space space space straight a subscript 12 equals 1 half
space space space space space straight a subscript 21 equals 2 over 1 equals 2 comma space space space space space straight a subscript 22 equals 2 over 2 equals 1
therefore space space space space straight A minus open square brackets table row 1 cell 1 half end cell row 2 1 end table close square brackets

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In the matrix straight A equals open square brackets table row 2 5 19 cell negative 7 end cell row 35 cell negative 2 end cell cell 5 over 12 end cell 12 row cell square root of 5 end cell 1 cell negative 5 end cell 17 end table close square brackets. space Write

(i) The order of the matrix
(ii) The number of elements,
(iii) Write the elements a13,a21 a33 a24’ a23


Here

straight A equals left parenthesis straight a subscript straight i right parenthesis equals open square brackets table row 2 5 19 cell negative 7 end cell row 35 cell negative 2 end cell cell 5 over 12 end cell 12 row cell square root of 5 end cell 1 cell negative 5 end cell 17 end table close square brackets. space Write

( i) Now A has 3 rows and 4 columns and so A is of order 3 x 4.

(ii) Number of elements = 3 x 4 = 12

(iii) a13, =- 19., a21 =35, a33 = 5, J24 = 12, a23 equals 5 over 2

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