Check the continuity of the function f given by f(x) = 2 x + 3 a
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Check the continuity of the function f given by f(x) = 2 x + 3 at x = 1.


Here space space space space space space space space space space space space space space space space space space space space space space space straight f left parenthesis straight x right parenthesis equals 2 straight x plus 3
Lt with straight x rightwards arrow 1 below space straight f left parenthesis straight x right parenthesis equals Lt with straight x rightwards arrow 1 below space left parenthesis 2 straight x plus 3 right parenthesis equals 2 left parenthesis 1 right parenthesis plus 3 equals 2 plus 3 equals 5
Now space straight f space is space defined space at space straight x equals 1
and space space straight f left parenthesis 1 right parenthesis equals 2 left parenthesis 1 right parenthesis plus 3 equals 2 plus 3 equals 5
therefore stack Lt space with straight x rightwards arrow 1 below space straight f left parenthesis straight x right parenthesis equals straight f left parenthesis 1 right parenthesis equals 5
therefore space straight f space is space continous space at space straight x equals 1.
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Examine whether the function f given by f(x) = x2 is continuous at x = 0.

Here space space straight f left parenthesis straight x right parenthesis equals straight x squared
Lt with straight x rightwards arrow 0 below space straight f left parenthesis straight x right parenthesis equals Lt with straight x rightwards arrow 0 below space straight x squared equals left parenthesis 0 right parenthesis squared equals 0
Now space straight f space is space defined space at space straight x equals 0
and space straight f left parenthesis 0 right parenthesis equals 0
therefore stack Lt space with straight x rightwards arrow 0 below straight f left parenthesis straight x right parenthesis equals straight f left parenthesis 0 right parenthesis equals 0
therefore space straight f space is space continous space at space straight x equals 0.
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Discuss the continuity of the function f given by f(x) = | x | at x = 0.


Here space space straight f left parenthesis straight x right parenthesis equals open vertical bar straight x close vertical bar
Lt with straight x rightwards arrow 0 to the power of minus below space space straight f left parenthesis straight x right parenthesis equals Lt with straight x rightwards arrow 0 to the power of minus below space open vertical bar straight x close vertical bar space space space space space space space left square bracket Put space straight x equals 0 minus straight h comma space straight h greater than 0 space so space that space straight h rightwards arrow 0 space as space straight x rightwards arrow 0 to the power of minus right square bracket
space space space space space space space space space space space equals Lt with straight x rightwards arrow 0 below space open vertical bar 0 minus straight h close vertical bar equals Lt with straight h rightwards arrow 0 below open vertical bar negative straight h close vertical bar equals Lt with straight h rightwards arrow 0 below space straight h equals 0
Lt with straight x rightwards arrow 0 to the power of plus below space straight f left parenthesis straight x right parenthesis equals Lt with straight x rightwards arrow 0 to the power of plus below space open vertical bar straight x close vertical bar space space space space space space space left square bracket Put space straight x equals 0 plus straight h comma space straight h greater than 0 space so space that space straight h rightwards arrow 0 space as space straight x rightwards arrow 0 plus right square bracket
space space space space space space space space space space space space space space space space space equals Lt with straight h rightwards arrow 0 below space open vertical bar 0 plus straight h close vertical bar equals Lt with straight h rightwards arrow 0 below space space open vertical bar straight h close vertical bar equals Lt with straight h rightwards arrow 0 below space straight h equals 0
Also space straight f space is space defined space at space straight x equals 0
and space space space space straight f left parenthesis 0 right parenthesis equals open vertical bar 0 close vertical bar equals 0
therefore space space Lt space straight f left parenthesis straight x right parenthesis equals Lt space straight f left parenthesis straight x right parenthesis equals straight f left parenthesis 0 right parenthesis
therefore space space space straight f space is space continous space at space straight x equals 0.
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Prove that the identity function on real numbers given by f(x) = x is continuous at every real number.

Here    f(x) = x
Function f is defined for all real numbers
Let c be any real number.
therefore space straight f left parenthesis straight c right parenthesis equals straight c
Also space Lt with straight x rightwards arrow straight c below space straight f left parenthesis straight x right parenthesis equals Lt with straight x rightwards arrow straight c below space straight x equals straight c
therefore space Lt with straight x rightwards arrow straight c below space straight f left parenthesis straight x right parenthesis equals space straight f left parenthesis straight c right parenthesis
∴ f is continuous at x = c
But c is any real number.
∴  f is continuous at every real number.

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Find all the points of discontinuity of the greatest integer function defined by f(x) = [x], where [x] denotes the greatest integer less than or equal to x.

Let f(x) = [ x ]. Df = R
Let a be any real number ∈ Df.
Two cases arise:
Case I. If a is not an integer, then
Lt with straight x rightwards arrow straight a below space straight f left parenthesis straight x right parenthesis equals space Lt with straight x rightwards arrow straight a below space left square bracket straight x right square bracket equals left square bracket straight a right square bracket equals straight f left parenthesis straight a right parenthesis
⇒ f is continuous at x = a

Case II. If a ∈ 1, then f(a) = [ a ] = a and
Lt with straight x rightwards arrow straight a to the power of minus below space straight f left parenthesis straight x right parenthesis equals space Lt with straight x rightwards arrow straight a to the power of minus below left square bracket straight x right square bracket equals straight a minus 1
Lt with straight x rightwards arrow straight a to the power of plus below straight f left parenthesis straight x right parenthesis equals Lt with straight x rightwards arrow straight a to the power of plus below space left square bracket straight x right square bracket equals straight a
therefore Lt with straight x rightwards arrow straight a to the power of minus below straight f left parenthesis straight x right parenthesis space not equal to Lt with straight x rightwards arrow straight a to the power of plus below space straight f left parenthesis straight x right parenthesis
∴ f is not continuous at x = a, a ∈ I.
∴ function is discontinuous at every integral point.

 

Tips: -

1. Domain of continuity for the function [x] is R – I.
 2. From the graph of [x], done in earlier class, it is also clear that [x] is discontinuous at integral points.

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