Find the indicated terms in the following sequence whose nth ter

Consider the sequence defined by tn = an2 + bn + c. If t2 = 3, t4 = 13 and t7 = 113, show that 3tn = 17n2 – 87n + 115


Here,                     straight t subscript straight n space equals space an squared plus bn plus straight c                              ...(i)

Now,                      <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
#1 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php(56): mkdir('/home/config_ad...', 493)
#2 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/FolderTreeStorageAndCache.class.php(110): com_wiris_util_sys_Store->mkdirs()
#3 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/RenderImpl.class.php(231): com_wiris_plugin_impl_FolderTreeStorageAndCache->codeDigest('mml=<math xmlns...')
#4 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/TextServiceImpl.class.php(59): com_wiris_plugin_impl_RenderImpl->computeDigest(NULL, Array)
#5 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/service.php(19): com_wiris_plugin_impl_TextServiceImpl->service('mathml2accessib...', Array)
#6 {main}</pre>       space space rightwards double arrow space space space space space space space space space space space space space space space space space space space space space<pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
#1 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php(56): mkdir('/home/config_ad...', 493)
#2 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/FolderTreeStorageAndCache.class.php(110): com_wiris_util_sys_Store->mkdirs()
#3 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/RenderImpl.class.php(231): com_wiris_plugin_impl_FolderTreeStorageAndCache->codeDigest('mml=<math xmlns...')
#4 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/TextServiceImpl.class.php(59): com_wiris_plugin_impl_RenderImpl->computeDigest(NULL, Array)
#5 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/service.php(19): com_wiris_plugin_impl_TextServiceImpl->service('mathml2accessib...', Array)
#6 {main}</pre>

rightwards double arrow          4a + 2b + c = 3                                               ...(ii)

                            space space straight t subscript 4 equals 13     rightwards double arrow                <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
#1 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php(56): mkdir('/home/config_ad...', 493)
#2 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/FolderTreeStorageAndCache.class.php(110): com_wiris_util_sys_Store->mkdirs()
#3 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/RenderImpl.class.php(231): com_wiris_plugin_impl_FolderTreeStorageAndCache->codeDigest('mml=<math xmlns...')
#4 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/TextServiceImpl.class.php(59): com_wiris_plugin_impl_RenderImpl->computeDigest(NULL, Array)
#5 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/service.php(19): com_wiris_plugin_impl_TextServiceImpl->service('mathml2accessib...', Array)
#6 {main}</pre>

rightwards double arrow           16a + 4b + c = 13                                          ...(iii)

                            space space straight t subscript 7 space equals space 113  rightwards double arrow                <pre>uncaught exception: <b>mkdir(): Permission denied (errno: 2) in /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php at line #56mkdir(): Permission denied</b><br /><br />in file: /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php line 56<br />#0 [internal function]: _hx_error_handler(2, 'mkdir(): Permis...', '/home/config_ad...', 56, Array)
#1 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/util/sys/Store.class.php(56): mkdir('/home/config_ad...', 493)
#2 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/FolderTreeStorageAndCache.class.php(110): com_wiris_util_sys_Store->mkdirs()
#3 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/RenderImpl.class.php(231): com_wiris_plugin_impl_FolderTreeStorageAndCache->codeDigest('mml=<math xmlns...')
#4 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/lib/com/wiris/plugin/impl/TextServiceImpl.class.php(59): com_wiris_plugin_impl_RenderImpl->computeDigest(NULL, Array)
#5 /home/config_admin/public/felixventures.in/public/application/css/plugins/tiny_mce_wiris/integration/service.php(19): com_wiris_plugin_impl_TextServiceImpl->service('mathml2accessib...', Array)
#6 {main}</pre>

rightwards double arrow           49a + 7b + c = 113                                         ...(iv)

Subtracting (iii) from (iv), we get   33a + 3b = 100                ...(v)

Subtracting (ii) from (iii), we get    12a + 2b = 10

rightwards double arrow              6a + b = 5                                                  ...(vi)

Multiplying both sides of (vi) by 3, we get

                 18a + 3b = 15                                               ...(vii)

Subtracting (vii) from (v), we get

                 15 straight a space equals space 85 space space space space space space space space space space space space space rightwards double arrow space space space space space space space space space space straight a space equals space 17 over 3
Using this value of a in (vi), we get

           6 open parentheses 17 over 3 close parentheses space plus space straight b space equals space 5        rightwards double arrow space space space 34 space plus space straight b space equals space 5 space space rightwards double arrow space space space straight b space equals space minus 29

Using values of a and b in (ii), we get

4 open parentheses 17 over 3 close parentheses plus 2 left parenthesis negative 29 right parenthesis plus straight c equals 3 space space space space rightwards double arrow space space straight c space equals space 3 space plus space 58 space minus 68 over 3 space equals space 61 minus 68 over 3 equals fraction numerator 183 minus 68 over denominator 3 end fraction space rightwards double arrow straight c equals space 115 over 3

Using values of a, b, c in (i), we get

             straight t subscript straight n space equals space 17 over 3 straight n squared minus 29 straight n space plus space 115 over 3 space rightwards double arrow space space 3 straight t subscript straight n space equals space 17 straight n squared minus 87 straight n plus 115

564 Views

Advertisement

Find the indicated terms in the following sequence whose nth terms are :
space space straight a subscript straight n space equals space fraction numerator straight n left parenthesis straight n minus 2 right parenthesis over denominator straight n plus 3 end fraction


Here, straight a subscript straight n space equals space fraction numerator straight n left parenthesis straight n minus 2 right parenthesis over denominator straight n plus 3 end fraction semicolon space space straight a subscript 19

Putting n = 19, we get straight a subscript 19 space equals space fraction numerator 19 left parenthesis 9 minus 2 right parenthesis over denominator 19 plus 3 end fraction space equals space fraction numerator 19 cross times 17 over denominator 22 end fraction equals 323 over 22

662 Views

Advertisement

Show that the sequence space space open curly brackets straight t subscript straight n close curly brackets defined by straight t subscript straight n space equals space nA space plus space straight B (where A and B are constant) is an A.P. with common difference A.


Here,    straight t subscript straight n space equals space nA space plus space straight B

Replacing n by n - 1, we get

         space space straight t subscript straight n minus 1 end subscript space equals space left parenthesis straight n minus 1 right parenthesis straight A space plus space straight B space equals space straight n space straight A space minus space straight A space plus space straight B

            straight d space equals space straight t subscript straight n space minus space straight t subscript straight n minus 1 end subscript space equals space left parenthesis nA space plus space straight B right parenthesis space minus space left parenthesis nA space minus space straight A space plus space straight B right parenthesis space equals space nA space plus space straight B space minus space nA space plus space straight A space minus space straight B space equals space straight A

which is constant and independent of n.

Hence, the sequencespace space open curly brackets straight t subscript straight n close curly brackets  is an A.P.

223 Views

Find the indicated terms in the following sequence whose nth terms are:
straight h left parenthesis straight n right parenthesis space equals space fraction numerator straight n squared plus 2 straight n over denominator 2 straight n end fraction semicolon space straight h left parenthesis straight n minus 1 right parenthesis comma space straight h left parenthesis 16 right parenthesis


Here,   straight h left parenthesis straight n right parenthesis space equals space fraction numerator straight n squared plus 2 straight n over denominator 2 straight n end fraction                                      ...(i)

Replacing n by n-1 in (1), we get

                      straight h left parenthesis straight n minus 1 right parenthesis space equals space fraction numerator left parenthesis straight n minus 1 right parenthesis squared plus 2 left parenthesis straight n minus 1 right parenthesis over denominator 2 left parenthesis straight n minus 1 right parenthesis end fraction space equals space fraction numerator straight n squared minus 2 straight n plus 1 plus 2 straight n minus 2 over denominator 2 left parenthesis straight n minus 1 right parenthesis end fraction space equals fraction numerator straight n squared minus 1 over denominator 2 left parenthesis straight n minus 1 right parenthesis end fraction space equals space fraction numerator straight n plus 1 over denominator 2 end fraction

Putting n = 16 in (I), we get straight h left parenthesis 16 right parenthesis space equals space fraction numerator 16 squared plus 2 left parenthesis 16 right parenthesis over denominator 2 left parenthesis 16 right parenthesis end fraction space equals space fraction numerator 256 plus 32 over denominator 32 end fraction space equals space 288 over 32 space equals space 9

                     

436 Views

Find the first six terms of the sequence whose first term is 1 and whose (n+l)th term is obtained by adding n to the nth term.


Let  straight t subscript straight n denote the nth term

               straight t subscript 1 space end subscript space equals space 1

According to given equation  straight t subscript straight n plus 1 end subscript space equals space straight t subscript straight n plus straight n                        ...(i)

Putting n = 1 in (i), we get          straight t subscript 1 plus 1 end subscript space equals space straight t subscript 1 plus 1 space equals space 1 plus 1 space equals space 2      rightwards double arrow space straight t subscript 2 space equals space 2

Putting n = 2 in (i), we get          straight t subscript 2 plus 1 end subscript space equals space straight t subscript 2 plus 2 space equals space 2 plus 2 space equals space 4    space space rightwards double arrow space space straight t subscript 3 space equals space 4

Putting n = 3 in (i), we get          straight t subscript 3 plus 1 end subscript space equals space straight t subscript 3 plus 3 space equals space 4 plus 3 equals 7      space space rightwards double arrow space space space space straight t subscript 4 space equals space 7 

Putting n = 4 in (i), we get         straight t subscript 4 plus 1 end subscript space equals space straight t subscript 4 plus 4 space equals space 7 space plus space 4 space equals space 11    rightwards double arrow space straight t subscript 5 equals 11

Putting n = 5 in (i), we get        straight t subscript 5 plus 1 end subscript space equals space straight t subscript 5 space plus space 5 space equals space 11 space plus space 5 space equals space 16   rightwards double arrow space straight t subscript 6 space equals space 16

580 Views

Advertisement