Given, mass of the coin = 3.0 g
Mass of atom = 62.92960 u
Each atom of the copper contains 29 protons and 34 neutrons.
Mass of 29 electrons = 29 x 0.000548 u
= 0.015892 u
Mass of nucleus = (62.92960 - 0.015892) u
= 62.913708 u
Mass of 29 protons = 29 x 1.007825 u
= 29.226925 u
Mass of 34 neutrons = 34 x 1.008665 u
= 34.29461 u
Total mass of protons and neutrons = (29.226925 + 34.29461) u
= 63.521535 u
Binding energy = (63.521535 - 62.913708) x 931.5 MeV
= 0.607827 x 931.5 MeV
Required energy =
Boron has two stable isotopes, Their respective masses are 10.01294 u and 11.00931 u, and the atomic mass of boron is 10.81u. Find the abundances of
Let, the relative abundance of be x%
Relative abundance of
Atomic weight = weighted average of the isotopes,
i.e.,
Given,
Mass of isotope 1 = 6.01512 u
Mass of isotope 2 = 7.01600 u
Abundance of isoptope 1 = 7.5 %
Abundance of isotope 2 = 92.5 %
Atomic mass of Li = weighted average of the isotopes
=
=