If one wishes to design a microarray chip for whole-genome expres

Subject

Life Sciences

Class

CNET Class 12

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 Multiple Choice QuestionsMultiple Choice Questions

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141.

If one wishes to design a microarray chip for whole-genome expression analysis of a eukaryotic system, which region of the gene should be preferred for selection of unique target sequences?

  • any region of the coding DNA sequence (CD)

  • 3' region of the CDS and 3' untranslated region (UTR)

  • 5' region of the CDS and 5' UTR

  • 1st intron only


B.

3' region of the CDS and 3' untranslated region (UTR)

The region of the gene that should be preferred for selection of unique target sequences should be 3' region of the CDS and 3' untranslated region (UTR).


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142.

For 5' end labeling of DNA, the following reactions are carried out sequentially as indicated.

5'-dephosphorylated DNA + [γ32P] dATP + T4-polynucelotide kinase (T4PNK) and incubated for 2 hours → ammonium acetate →tris-EDTA → ethanol

If trace amount of NH4+ is present in the initial DNA mix, which of the following statements would most likely be true?

  • NH4+ ion activates T4PNK, thereby increasing the labeling efficiency.

  • NH4+ ion inhibits T4PNK, therefore should not be present in the DNA mix.

  • NH4+ ion does not have any effect on T4PNK.

  • NH4+ ion dephosphorylates DNA, thereby increasing the labeling efficiency.


143.

Four different receptors viz, A, B, C, and D bond to the same ligand X. In order to determine which receptor has the highest binding affinity following experiment was carried out. Cells were transfected with green fluorescence protein (GFP)-tagged receptors (A, B, C, and D) individually, then incubated with red fluorescence (RFP)-tagged -'X' and subjected to FACS analysis. Following are the results

Which receptor has the highest ligand binding affinity?

  • A

  • B

  • C

  • D


144.

During line transect sampling of two solitary species of ground mammals the following observation was made:
    Smaller species Larger species
A Transect length 100 km 100 km
B No. of animals sighted 30 36
C Mean perpendicular distance from transect line 10 m 40 m

Which of the following can be inferred from the data?

  • The smaller species is ore abundant but seen less frequently.

  • The smaller species are less abundant and seen less frequently.

  • The larger species are more abundant but seen less frequently.

  • The larger species are seen more frequently, but its abundance cannot be compared with the smaller species.


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145.

A protein contains 2 Trp and 4 Tyr residues. The molecular mass of the protein is 17000 D and that of Trp and try ae 204 and 180 D respectively. Values of E, the absorption coefficient of 1% (g/ v) solutions of Trp and Tyr in a 1-cm cell at 280 nm, are 269.60 and 8.33 respectively. The absorption of 1 mg/ ml protein solution in 1-cm cell at 280 nm will be:

  • 0.1

  • 1.0

  • 0.7

  • 1.7


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