KO2 exhibits paramagnetic behaviour. This is due to the para

Subject

Chemistry

Class

JEE Class 12

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31.

KO2 exhibits paramagnetic behaviour. This is due to the paramagnetic nature of

  • KO-

  • K+

  • O2

  • O-2


D.

O-2

In KO2 oxygen exists as O2- ion. Its molecular orbital electronic configuration is as follows

Due to presence of 1 unpaired electron in anti bonding molecular orbital, it is paramagnetic in behavour.


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32.

Which one of the following ions has same number of unpaired electrons as those present in V+ ion?

  • Fe3+

  • Ni2+

  • Mn2+

  • Cr3+


33.

Match the following
Column I  Column II
(A) sp3 (i) [Co(NH3)6]3+
(B) dsp2 (ii) [Ni(CO)4]
(C) sp3d2 (iii) [Pt(NH3)2Cl2]
(D) d2sp3 (iv) [CoF6]3-
  (v) [Fe(CO)5]

  • A    B    C    D

    (v) (ii)  (i)  (iii)

  • A    B    C    D

    (ii)  (iii) (iv) (v)

  • A    B    C    D

    (ii) (iii) (i)  (v)

  • A    B     C     D

    (iii) (ii)  (iv)  (i)


34.

What is Z in the following reaction sequence?

  • C6H5CO2H

  • C6H5OH

  • C6H5CHO

  • C6H6


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35.

CH3MgBr + CO2 Dryether Y H3O Z . Identify Z from the following.

  • Ethyl acetate

  • Acetic acid

  • Propanoic acid

  • Methyl acetate.


36.

X Y Benzoquinone. Identify X and Y inthe above reaction.

  • X Y
    Zn
  • X Y
    Na2Cr2O7/ H2SO4
  • X Y
    Na2Cr2O7/ H2SO4
  • X Y
    Zn

37.

C6H5- O- CH2- CH3, HI Y+ Z

Identify Y and Z inthe above reaction.

  •  

    X Y
    C6H5OH H3CCH3
  •  

    X Y
    C2H5I C6H5CHO
  • X Y
    C6H5I H3CCH2OH
  • X Y
    C6H5OH H3CCH2I

38.

What are the substances which mimic the natural chemical messengers?

  • Antibiotics

  • Antagonists

  • Agonists

  • Receptors


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39.

Lactose is disaccharide of

  • α- D - glucose and α- D - fructose

  • β- D- glucose and β- D-galatose

  • α- D - glucose and  β- D-ribose

  • α- D - glucose and  β- D-galactose


40.

Identify the copolymer from the following


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