Consider the following sets of quantum numbers. Which of the following setting is not permissible arrangement of electrons in an atom?
n = 4; l = 0; m = 0; s =
n = 5; l = 3; m = 0; s =
n = 3; l = 2; m = -2; s =
n = 3; l = 2; m = -3; s =
D.
n = 3; l = 2; m = -3; s =
For a given value of n,
l = 0 to n - 1
m = +l, 0, -l
s =
Thus, option d is the correct answer.
HCl gas is covalent and NaCl is an ionic compound. This is because
sodium is highly electropositrve
hydrogen is a non-metal
HCl is a gas
electronegativity difference between H and Cl is less than 2.1
Main axis of diatomic molecule is z. The orbitals px and py overlap to form
-molecular orbital
σ-molecular orbital
δ-molecular orbital
No bond is formed
An organic compound contains C = 40%, H = 13.33% and N = 46.67%. Its empirical formula is
C2H2N
C3H7N
CH4N
CHN
Benzene carbaldehyde is reacted with conc. NaOH solution to give the products A and B. The product A can be used as a food preservative and the product B is an aromatic hydroxy compound, where -OH group is linked to sp3-hybridised C-atom next to benzene ring. The products A and B respectively are
sodium benzoate and phenol
sodium benzoate and phenyl methanol
sodium benzoate and cresol
sodium benzoate and picric acid
An organic compound A on reduction gives compound B, which on reaction with trichloromethane and caustic potash forms C. The compound C on catalytic reduction gives N-methyl benzenamine, the compound A is,
nitrobenzene
nitromethane
methanamine
benzenamine
The hybridisation of C in diamond, graphite and ethyne is in the order.
sp3, sp, sp2
sp3, sp2, sp
sp, sp2, sp3
sp2, sp3, sp