The solution of the differential equation is :
y(1 + x2) = c + tan-1(x)
y1 + x2 = c + tan-1x
y1 + x2 = c + sin-1x
A.
dydx + 2yx1 + x2 = 11 + x22On comparing the given differential equation with linear differential equation dydx + py = QWe get P = 2x1 + x2 and Q = 11 + x22Now, IF = e∫Pdx = e∫2x/1 + x2dx = elog1 + x2 = 1 + x2⇒ y1 + x2 = ∫11 + x221 + x2dx + c⇒ y1 + x2 = ∫11 + x2dx + c⇒ y1 + x2 = c + tan-1x
The solution of the differential equation xdy - ydx = x2 + y2dx is :
x+ x2 + y2 = cx2
y- x2 + y2 = cx
x - x2 + y2 = cx
y+ x2 + y2 = cx2
The solution of the differential equation dydx = ex - y + x2e- y is :
y = ex - y + x2e- y + c
ey - ex = 13x3 + c
ey + ex = 13x3 + c
ex - ey = 13x3 + c